document.write( "Question 470907: the sum of the squares of two consecutive positive integers is nine more than 8 times the smaller. Find the integers. \n" ); document.write( "

Algebra.Com's Answer #322989 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi,
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document.write( "Let x and (x+1) represent the two consecutive positive integers
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document.write( "Question states***
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document.write( " x^2 + (x+1)^2 = 8x + 9
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document.write( "x^2 + x^2 + 2x + 1 = 8x +9
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document.write( "   2x^2 -6x - 8 = 0
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document.write( "    x^2 - 3x - 4 = 0
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document.write( "factoring
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document.write( "   (x-4)(x+1) = 0
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document.write( "   (x-4) = 0   x = 4    Integers are 4,5
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document.write( "   (x+1) = 0   x = -1  Toss out, looking for positive pair\r
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document.write( "CHECKING our Answer***
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document.write( "  16 + 25 = 41 = 32+9
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