document.write( "Question 470865: The height in feet of an object thrown upward is given by the equation h=80t-16t^2, where is the height of the object after 1 seconds. after how many seconds does the object reach its maximum height? \n" ); document.write( "
Algebra.Com's Answer #322975 by nerdybill(7384)\"\" \"About 
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The height in feet of an object thrown upward is given by the equation h=80t-16t^2, where is the height of the object after 1 seconds.
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\n" ); document.write( "set t to 1 and solve for h:
\n" ); document.write( "h=80t-16t^2
\n" ); document.write( "h=80(1)-16(1)^2
\n" ); document.write( "h=80-16
\n" ); document.write( "h=64 feet
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\n" ); document.write( "after how many seconds does the object reach its maximum height?
\n" ); document.write( "find the \"axis of symmetry\":
\n" ); document.write( "t = -b/(2a)
\n" ); document.write( "t = -80/(2(-16))
\n" ); document.write( "t = -80/(-32)
\n" ); document.write( "t = 2.5 seconds
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