document.write( "Question 470819: Find the equation in standard form of the hyperbola with an asymptote slope of 3/4 and foci (-2,-8) and (8,-8).\r
\n" ); document.write( "\n" ); document.write( "a.(x-3)^2/9-(y+8)^2/16=1
\n" ); document.write( "b.(y-3)^2/16-(x+8)^2/9=1
\n" ); document.write( "c.(y+8)^2/9-(x-3)^2/9=1
\n" ); document.write( "d.(x-3)^2/16-(y+8)^2/9=1
\n" ); document.write( "e.(x+8)^2/9-(y-3)^2/16=1 \n" ); document.write( "
Algebra.Com's Answer #322969 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
 
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document.write( "Hi,
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document.write( "Standard Form of an Equation of an Hyperbola is  \"%28x-h%29%5E2%2Fa%5E2+-+%28y-k%29%5E2%2Fb%5E2+=+1\" 
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document.write( "where Pt(h,k) is a center  with vertices 'a' units right and left of center.
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document.write( "Asymptotes passing thru the center with slope = ± b/a 
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document.write( "foci being ± sqrt(a^2 + b^2)from center  along axis of symmetry y = k
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document.write( "asymptote slope b/a = 3/4   \"%28x-h%29%5E2%2F16+-+%28y-k%29%5E2%2F9+=+1\" 
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document.write( "foci (-2,-8) and (8,-8). c = sqrt(16+9) = 5, C(3,-8) \"%28x-3%29%5E2%2F16+-+%28y%2B8%29%5E2%2F9+=+1\" 
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