document.write( "Question 470860: A curve has the equation \"y+=+%28ax%2B3%29ln%28x%29\", where x is greater than zero and a is a constant. The normal to the curve at the point where the curve crosses the x-axis is parallel to the line \"5y+%2B+x+=+2\". Find the value of a.\r
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\n" ); document.write( "\n" ); document.write( "*Please answer as soon as possible bro : =)
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Algebra.Com's Answer #322958 by Tatiana_Stebko(1539)\"\" \"About 
You can put this solution on YOUR website!
if the equation of the curve is y = f(x) then the slope of the normal line is m=-1/(f'(x0))
\n" ); document.write( "f'(x)=((ax+3)lnx)'=(ax+3)'lnx+(ax+3)(lnx)'=a*lnx+(ax+3)/x
\n" ); document.write( " the point where the curve crosses the x-axis is (x0,0)
\n" ); document.write( "find xo
\n" ); document.write( "Put into the curve equation y=0
\n" ); document.write( "\"%28ax%2B3%29lnx=0\"
\n" ); document.write( "\"x=1\"
\n" ); document.write( "then m=f'(x0)=f'(1)=\"a%2Aln1%2B%28a%2B3%29%2F1=a%2B3\"
\n" ); document.write( "the slope of the normal line to the curve at the point where the curve crosses the x-axis is -1/(f'(1))=\"-1%2F%28a%2B3%29\"
\n" ); document.write( "If normal is parallel to the line \"5y+%2B+x+=+2\", then their slopes are equal
\n" ); document.write( "\"5y+%2B+x+=+2\"=> \"5y=-x%2B2\"=> \"y=%28-1%2F5%29x%2B2%2F5\"=> the slope \"m=-1%2F5\"
\n" ); document.write( " \"-1%2F%28a%2B3%29=-1%2F5\"
\n" ); document.write( "\"a%2B3=5\"
\n" ); document.write( "\"a=2\"\r
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