document.write( "Question 470851: find two numbers which differs by 5 and sum of their squares are 125. \n" ); document.write( "
Algebra.Com's Answer #322951 by hinaahsan(5)\"\" \"About 
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let the two numbers be x and x-5 \r
\n" ); document.write( "\n" ); document.write( "(x)^2 + (x-5)^2 = 125
\n" ); document.write( " x^2 + x^2 + 25 -10x =125
\n" ); document.write( " 2x^2 - 10x +25 =125
\n" ); document.write( " 2x^2 -10x= 125-25
\n" ); document.write( " 2x^2 -10x =100
\n" ); document.write( " 2x(x-10) = 100
\n" ); document.write( " x(x-10) = 100/2
\n" ); document.write( " x(x-10)=50
\n" ); document.write( " x^2-10x-50 = 0
\n" ); document.write( " x^2 -10x +5x -50 =0
\n" ); document.write( " x(x-10) +5(x-10) =0
\n" ); document.write( " (x+5)(x-10) = 0
\n" ); document.write( "(x+5) = 0 ; (x-10)=0
\n" ); document.write( "x= -5 ; x=10\r
\n" ); document.write( "\n" ); document.write( "so the two numbers be -5 and 10\r
\n" ); document.write( "\n" ); document.write( "Counter check
\n" ); document.write( " (-5)^2 + (10)^2
\n" ); document.write( "= 25+100
\n" ); document.write( "= 125
\n" ); document.write( "
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