document.write( "Question 470798: During the first part of a trip, a canoeist travels 73 miles at a certain speed. The canoeist travels 14 miles on the second part of the trip at a speed 5mph slower. The total time for the trip is 3 hrs. What was the speed on each part of the trip?\r
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document.write( "1.Speed of 1st part of the trip?\r
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document.write( "2.Speed of 2nd part of the trip? \n" );
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Algebra.Com's Answer #322938 by mananth(16946)![]() ![]() You can put this solution on YOUR website! first part x mph \n" ); document.write( "second part -5 mph \n" ); document.write( " \n" ); document.write( "first part 73 miles \n" ); document.write( "second part 14 miles \n" ); document.write( " \n" ); document.write( "speed in first part x mph \n" ); document.write( "speed second part x -5 mph \n" ); document.write( "Total rowing time 3 hours \n" ); document.write( "Time first part 73 / x \n" ); document.write( "Time second part 14 / ( x -5 ) \n" ); document.write( " \n" ); document.write( "Time first part + time second part =3 hours \n" ); document.write( " \n" ); document.write( "73/x+14/(x-5)=3 \n" ); document.write( "LCD =x* (x-5) \n" ); document.write( "multiply the equation by the LCD \n" ); document.write( "we get \n" ); document.write( "73*(x-5)+14x=3 \n" ); document.write( "73x-365 +14x= 3X^2-15x \n" ); document.write( "102x-365 =3x^2 \n" ); document.write( "3X^2-102 x+365 = 0 \n" ); document.write( "3x^2-102 x+365=0 \n" ); document.write( "/3 \n" ); document.write( "x^2-34x+ 121.67= 0 \n" ); document.write( " \n" ); document.write( "Find the roots of the equation by quadratic formula \n" ); document.write( " \n" ); document.write( "a= 1 b= -34 c= 121.67 \n" ); document.write( " \n" ); document.write( "b^2-4ac= 1156 - -486.68 \n" ); document.write( "b^2-4ac= 669.32 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "x1=( 34 + 25.87 )/ 2 \n" ); document.write( "x1= 29.94 \n" ); document.write( "x2=( 34 -25.87 ) / 2 \n" ); document.write( "x2= 4.06 \n" ); document.write( " \n" ); document.write( "x = 29.94 mph first part \n" ); document.write( "24.94 mph second part \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |