document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=470809>Question 470809</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Base of a Triangle is 3feet more than 3 times its height. If the area is 30feet, find the height and base of the triangle. I''m trying to understand this question but don't get the formulas, and the 3time its height part is really confusing me. please help. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #322937 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=322937\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> height = x<BR>\n" );
document.write( "base = 3x+3<BR>\n" );
document.write( "Area = 30 ft^2<BR>\n" );
document.write( "Area of triangle = 1/2 * base * height\r<BR>\n" );
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document.write( "30=1/2 *x*(3x+3)\r<BR>\n" );
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document.write( "multiply by 2\r<BR>\n" );
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document.write( "60= 3x^2+3x\r<BR>\n" );
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document.write( "3x^2 +3x-60=0<BR>\n" );
document.write( "/3<BR>\n" );
document.write( "x^2+x-20=0<BR>\n" );
document.write( "x^2+5x-4x-20<BR>\n" );
document.write( "x(x+4)-4(x+5)=0<BR>\n" );
document.write( "(x+5)(x-4)=0<BR>\n" );
document.write( "x=4 OR -5 ignore negative value<BR>\n" );
document.write( "height = 4 feet<BR>\n" );
document.write( "base = 4*3+3=15 feet\r<BR>\n" );
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document.write( " </SPAN>\n" );
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