document.write( "Question 470766: Evaluate: 8C3
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Algebra.Com's Answer #322916 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "Since order does not matter, we must use the combination formula:\r
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\n" ); document.write( "\n" ); document.write( "\"n%21%2F%28n-r%29%21r%21\" Start with the given formula\r
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\n" ); document.write( "\n" ); document.write( "\"8%21%2F%288-3%29%213%21\" Plug in \"n=8\" and \"r=3\"\r
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\n" ); document.write( "\n" ); document.write( "\"8%21%2F5%213%21\" Subtract \"8-3\" to get 5\r
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\n" ); document.write( "\n" ); document.write( "Expand 8!
\n" ); document.write( "\"%288%2A7%2A6%2A5%2A4%2A3%2A2%2A1%29%2F5%213%21\"\r
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\n" ); document.write( "\n" ); document.write( "Expand 5!
\n" ); document.write( "\"%288%2A7%2A6%2A5%2A4%2A3%2A2%2A1%29%2F%285%2A4%2A3%2A2%2A1%293%21\"\r
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\n" ); document.write( "\n" ); document.write( "\"%288%2A7%2A6%2Across%285%2A4%2A3%2A2%2A1%29%29%2F%28cross%285%2A4%2A3%2A2%2A1%29%293%21\" Cancel\r
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\n" ); document.write( "\n" ); document.write( "\"%288%2A7%2A6%29%2F3%21\" Simplify\r
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\n" ); document.write( "\n" ); document.write( "Expand 3!
\n" ); document.write( "\"%288%2A7%2A6%29%2F%283%2A2%2A1%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"336%2F%283%2A2%2A1%29\" Multiply 8*7*6 to get 336\r
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\n" ); document.write( "\n" ); document.write( "\"336%2F6\" Multiply 3*2*1 to get 6\r
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\n" ); document.write( "\n" ); document.write( "\"56\" Now divide\r
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\n" ); document.write( "\n" ); document.write( "So 8 choose 3 (where order doesn't matter) yields 56 unique combinations
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