document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=470739>Question 470739</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please complete the factored form of the polynomial\r<BR>\n" );
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document.write( "f(x)=6x^3+2x^2-16x+8 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #322904 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=322904\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Please complete the factored form of the polynomial <BR>\n" );
document.write( "f(x)=6x^3+2x^2-16x+8<BR>\n" );
document.write( "**<BR>\n" );
document.write( "If you are allowed to use a calculator, you will find that 1 is one of the roots. The other two roots can be found by long division or synthetic division. I will use the latter method.<BR>\n" );
document.write( "0).......6......2......-16.....8<BR>\n" );
document.write( "1)...............6.........8....-8<BR>\n" );
document.write( "..........6......8.......-8......0<BR>\n" );
document.write( "f(x)=(x-1)(6x^2+8x-8)<BR>\n" );
document.write( "6x^2+8x-8=0<BR>\n" );
document.write( "3x^2+4x-4=0<BR>\n" );
document.write( "(3x-2)(x+2)=0<BR>\n" );
document.write( "3x-2=0<BR>\n" );
document.write( "x=2/3<BR>\n" );
document.write( "x+2=0<BR>\n" );
document.write( "x=2<BR>\n" );
document.write( "..<BR>\n" );
document.write( "f(x)=(x-1)(3x-2)(x+2) </SPAN>\n" );
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