document.write( "Question 470628: The airplane could fly 2080 miles in 5 more hours than it took the sports car to drive 195 miles. The speed of the airplane was 4 times the speed of the sports car. Find the speeds and times of both \n" ); document.write( "
Algebra.Com's Answer #322865 by monika_p(71)\"\" \"About 
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for the airplane d=2080, t=t1+5, and v=4*v1
\n" ); document.write( "for the car d1=195, t1=? , and v1=?\r
\n" ); document.write( "\n" ); document.write( "speed formula
\n" ); document.write( "\"v=d%2Ft\"\r
\n" ); document.write( "\n" ); document.write( "for the airplane we can write:\r
\n" ); document.write( "\n" ); document.write( "\"4%2Av1=2080%2F%28t1%2B5%29\"\r
\n" ); document.write( "\n" ); document.write( "for the car\r
\n" ); document.write( "\n" ); document.write( "\"v1=195%2Ft1\"\r
\n" ); document.write( "\n" ); document.write( "since the first equation for airplane has 2 unknown lets substitute v1 from 2nd equation\r
\n" ); document.write( "\n" ); document.write( "\"4%2A195%2Ft1=2080%2F%28t1%2B5%29\"
\n" ); document.write( "\"780%2Ft1-2080%2F%28t1%2B5%29=0\"
\n" ); document.write( "\"%28780%28t1%2B5%29-2080t1%29%2Ft1%28t1%2B5%29=0\"
\n" ); document.write( "\"780t1%2B3900-2080t1=0\"
\n" ); document.write( "1300t1=3900
\n" ); document.write( "t1=3\r
\n" ); document.write( "\n" ); document.write( "then \"v1=195%2F3=65\"\r
\n" ); document.write( "\n" ); document.write( "t=t1+5 = 8
\n" ); document.write( "v=4*v1=4*65=260
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