document.write( "Question 470625: if sinx=1/3, secy=5/3. fine the exact values of
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document.write( "a) tan(x+y)
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document.write( "b) cos (x-y)
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document.write( "c) sin^2(x) + cos^2(y)\r
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document.write( "can anyone show me how can i atleast start the question? method?
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document.write( "thanks \n" );
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Algebra.Com's Answer #322863 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! if sinx=1/3, secy=5/3. fine the exact values of \n" ); document.write( "a) tan(x+y) \n" ); document.write( "b) cos (x-y) \n" ); document.write( "c) sin^2(x) + cos^2(y) \n" ); document.write( "------------- \n" ); document.write( "sin(x) = 1/3 \n" ); document.write( " \n" ); document.write( "--------- \n" ); document.write( "tan(x) = sin(x)/cos(x) = sqrt(2)/4 \n" ); document.write( "----------------- \n" ); document.write( "sec(y) = 5/3 \n" ); document.write( "cos(y) = 3/5 \n" ); document.write( "sin(y) = 4/5 \n" ); document.write( "tan(y) = sin(y)/cos(y) = 4/3 \n" ); document.write( "------------ \n" ); document.write( "a) \n" ); document.write( "= \n" ); document.write( "= \n" ); document.write( "= \n" ); document.write( "= \n" ); document.write( "=~ 3.191 \n" ); document.write( "-------------------- \n" ); document.write( "b) cos (x-y) \n" ); document.write( "= cos(x)cos(y) + sin(x)sin(y) \n" ); document.write( "= \n" ); document.write( "= \n" ); document.write( "=~ 0.832352 \n" ); document.write( "------------ \n" ); document.write( "c) sin^2(x) + cos^2(y) \n" ); document.write( "= 1/9 + 9/25 \n" ); document.write( "= 106/225 \n" ); document.write( " \n" ); document.write( " |