document.write( "Question 470613: Suppose a standard die is rolled twice. Let A be the event a 3 occurs on the first roll, let B be the event that the sum of the two rolls is 7, and let C be the event that the same number is rolled both times.
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Algebra.Com's Answer #322851 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi,
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document.write( "Event A, 3 on the 1st roll  P(A) = 6/36 = 1/6
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document.write( "Event B, sum is 7    P(B) = 6/36 = 1/6
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document.write( "Event C, double      P(C) =  6/36 = 1/6
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document.write( "If events are independent, then the probability of them both occurring is the
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document.write( " product of the probabilities of each occurring. 
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document.write( "P(A and B)= P(A)*P(B) = 1/6*1/6 = 1/36 = P(both occur) a 3 rolled and then a 4
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document.write( "  Events A and B are Independent  
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document.write( "___1_2_3__4__5__6  (First roll)
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document.write( "1|_2_3_4__5__6__7
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document.write( "2|_3_4_5__6__7__8
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document.write( "3|_4_5_6__7__8__9
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document.write( "4|_5_6___8__9_10
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document.write( "5|_6_7_8__9_10_11
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document.write( "6|_7_8_9_10_11_12
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