document.write( "Question 470581: determin the equation of the line perpendicular to the line 3y+4x=1 passing through the point (-1,2) \n" ); document.write( "
Algebra.Com's Answer #322781 by mananth(16946)\"\" \"About 
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4 x + 3 y = 1
\n" ); document.write( "Find the slope of this line
\n" ); document.write( "3y = -4 x + 1
\n" ); document.write( "Divide by 3
\n" ); document.write( " y = -4/3 x + 0.33
\n" ); document.write( "Compare this equation with y=mx+b
\n" ); document.write( "slope m = -4/3
\n" ); document.write( "The slope of a line perpendicular to the above line will be the negative reciprocal = 3/4
\n" ); document.write( "m1*m2=-1
\n" ); document.write( "The slope of the required line will be 0.75 0.75 = 0.75
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\n" ); document.write( "m= 3/4 ,point (-1,2)
\n" ); document.write( "Find b by plugging the values of m & the point in
\n" ); document.write( "y=mx+b
\n" ); document.write( "2=-0.75 + b
\n" ); document.write( "b= 2.75= 9/4
\n" ); document.write( "m= 3/4
\n" ); document.write( "The required equation is y= 3/ 4 x+9/4
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