document.write( "Question 470600: Help me find the real solutions of the equation by factoring:\r
\n" ); document.write( "\n" ); document.write( "x to the 3rd power + 2x(square) - 16x - 32 = 0
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Algebra.Com's Answer #322776 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
First, we must factor.\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E3%2B2x%5E2-16x-32\" Start with the given expression\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%5E3%2B2x%5E2%29%2B%28-16x-32%29\" Group like terms\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%28x%2B2%29-16%28x%2B2%29\" Factor out the GCF \"x%5E2\" out of the first group. Factor out the GCF \"-16\" out of the second group\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%5E2-16%29%28x%2B2%29\" Since we have the common term \"x%2B2\", we can combine like terms\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B4%29%28x-4%29%28x%2B2%29\" Now factor \"x%5E2-16\" to get \"%28x%2B4%29%28x-4%29\" (this a difference of squares)\r
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\n" ); document.write( "\n" ); document.write( "So \"x%5E3%2B2x%5E2-16x-32\" factors to \"%28x%2B4%29%28x-4%29%28x%2B2%29\"\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"x%5E3%2B2x%5E2-16x-32=%28x%2B4%29%28x-4%29%28x%2B2%29\"\r
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\n" ); document.write( "\n" ); document.write( "So this essentially means that \"x%5E3%2B2x%5E2-16x-32=0\" becomes \"%28x%2B4%29%28x-4%29%28x%2B2%29=0\"\r
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\n" ); document.write( "\n" ); document.write( "Now we move onto solving \"%28x%2B4%29%28x-4%29%28x%2B2%29=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B4%29%28x-4%29%28x%2B2%29=0\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"x%2B4=0\" or \"x-4=0\", or \"x%2B2=0\" Use the zero product property\r
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\n" ); document.write( "\n" ); document.write( "\"x=-4\" or \"x=4\", or \"x=-2\" Solve for 'x' in each equation.\r
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\n" ); document.write( "\n" ); document.write( "So the three solutions are \"x=-4\" or \"x=4\", or \"x=-2\"\r
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