document.write( "Question 470587: solve for x x = log366 \n" ); document.write( "

Algebra.Com's Answer #322755 by bucky(2189) $\"\"$ $\"About$

You can put this solution on YOUR website!
Your problem is to solve:
\n" ); document.write( ".
\n" ); document.write( " $\"x+=+log366\"$
\n" ); document.write( ".
\n" ); document.write( "without any further instructions, the normal practice is to assume that the term \"log\" refers to the base 10. And $\"log366\"$ is just a number that you would normally look up by entering 366 on a scientific calculator and then pressing the \"log\" key.
\n" ); document.write( ".
\n" ); document.write( "When I did this I got the answer 2.563481085
\n" ); document.write( ".
\n" ); document.write( "Since we are in the base 10, this answer is the exponent that you raise 10 to in order to get 366. So we say:
\n" ); document.write( ".
\n" ); document.write( " $\"10%5E2.563481085+=+366\"$
\n" ); document.write( ".
\n" ); document.write( "Note that there is no normal way to come up with $\"x+=+2.563481085\"$ short of looking it up in a table of logarithms (not usually as accurate as a calculator), using a scientific calculator as above, or from the old days, using a slide rule (in no way as accurate as a calculator).
\n" ); document.write( ".
\n" ); document.write( "Hope this helps you to understand logarithms a little better.
\n" ); document.write( " \n" ); document.write( "

\n" );