document.write( "Question 424509: A sample of 83 golfers showed that their average score on a particular golf course was 84.81 with a standard deviation of 5.99.
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document.write( "Answer each of the following (show all work
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document.write( "and state the final answer to at least two decimal places.):
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document.write( "(A) Find the 90% confidence interval of the mean score for all 83 golfers.
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document.write( "(B) Find the 90% confidence interval of the mean score for all golfers if this is a sample of 130 golfers instead of a sample of 83.
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document.write( "(C) Which confidence interval is larger and why?
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Algebra.Com's Answer #322649 by ednurse73(1)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " |