document.write( "Question 470288: How do I check my answer for this problem? How do I check for for extraneous solutions. What is extraneous solution? How does it happen?\r
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Algebra.Com's Answer #322600 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!

 
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document.write( "Hi,
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document.write( "Question states***
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document.write( "sqrt(x+3)=x+1
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document.write( "   (x+3) = (x+1)^2
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document.write( "   x+3 = x^2 + 2x+ 1
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document.write( "   x^2 + x - 2 = 0
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document.write( "factoring
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document.write( "  (x +2)(x-1) = 0
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document.write( "  (x +2)= 0   x = -2
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document.write( "  (x-1) = 0   x = 1\r
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document.write( "CHECKING our Answers***
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document.write( "  sqrt(1)≠ -1, x= -2 is an Extraneous solution
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document.write( "  sqrt(4) = 2   x = 1 is the Solution \n" );
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