document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=470271>Question 470271</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A boy traveling by a canoe can go downstream 6 miles per hour and upstream 2 miles per hour. How fast can he go in still water, and what is the rate of the current? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #322584 by </B><A HREF=/tutors/aboutme.mpl?userid=Gogonati><B>Gogonati(855)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Gogonati><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Gogonati><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=322584\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the rate of the current be x miles per hour.The speed of the canoe  downstream will be: 6-x, and upstream 2+x.Since the rate of the current does not change we write: 6-x=2+x, solving this equation we get x=2 miles per hour, is the  rate of change of the current.<BR>\n" );
document.write( "Answer:On still water the canoe travel 6-2=4 or 2+2=4 miles per hour, and the rate of the current is 2 miles/h. </SPAN>\n" );
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