document.write( "Question 470268: the perimeter of a rectangle is 18 feet and the area of the rectanggle is 20 feet what is the width of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #322578 by Gogonati(855)\"\" \"About 
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Half of the perimeter is 9 feet and its equal L+W=9. Let the W=x, then L=9-x, and the area is equal A=LxW, substituting we get:\r
\n" ); document.write( "\n" ); document.write( "\"20=x%289-x%29\" write this equation in standard form \"x%5E2-9x%2B20=0\", and solve \r
\n" ); document.write( "\n" ); document.write( "it by factoring \"%28x-5%29%28x-4%29=0\". Set to zero each factor to find the roots:\r
\n" ); document.write( "\n" ); document.write( "x-5=0 <=> x=5, and x-4=0 <=> x=4.\r
\n" ); document.write( "\n" ); document.write( "Answer:The width of the rectangle is 4 feet and its length 5 feet.
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