document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=462549>Question 462549</A>: <I><SPAN STYLE=\"word-break: break-all;\">  A triangle has a 20 degree angle, a 40 degree angle and a 120 degree angle. The length of the side opposite the 20 degree angle is 3 inches. Find the lengths of the other two sides.\r<BR>\n" );
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document.write( "My answer I got was 2.52 and 3.92 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #322544 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=322544\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A triangle has a 20 degree angle, a 40 degree angle and a 120 degree angle. The length of the side opposite the 20 degree angle is 3 inches. Find the lengths of the other two sides. <BR>\n" );
document.write( "My answer I got was 2.52 and 3.92<BR>\n" );
document.write( "..<BR>\n" );
document.write( "Mark angles 20º, 40º and 120º, A, B and C, respectively. Mark corresponding opposite sides a=3, b, and c<BR>\n" );
document.write( "Using Law of Sines:<BR>\n" );
document.write( "sin A/a=sin B/b<BR>\n" );
document.write( "sin 20/3=sin 40/b<BR>\n" );
document.write( "b=3*sin 40/sin 20=5.64<BR>\n" );
document.write( "..<BR>\n" );
document.write( "sin A/a=sin C/c<BR>\n" );
document.write( "sin 20/3=sin 120/c<BR>\n" );
document.write( "c=3*sin 120/sin 20=7.60<BR>\n" );
document.write( "ans:<BR>\n" );
document.write( "3 sides are: 3, 5.64, and 7.60 </SPAN>\n" );
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