document.write( "Question 470139: This question seems to make no sense to me , at a point i thought i had something but i just cant solve pleasee help me:\r
\n" ); document.write( "\n" ); document.write( "Two points on the circle given by the equation (x-1)^2+(y+3)^2=100 have x-coordinate -7.what is the y coordinates of those two points?
\n" ); document.write( "now that i reread this problem im thinking the numbers in the actual equation are irrelevant but im not sure. your help is appreciated thsnk you.
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Algebra.Com's Answer #322503 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"%28x-1%29%5E2%2B%28y%2B3%29%5E2=100\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"%28-7-1%29%5E2%2B%28y%2B3%29%5E2=100\" Plug in x=-7. The goal now is to solve for y.\r
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\n" ); document.write( "\n" ); document.write( "\"%28-8%29%5E2%2B%28y%2B3%29%5E2=100\" Subtract\r
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\n" ); document.write( "\n" ); document.write( "\"64%2B%28y%2B3%29%5E2=100\" Square -8 to get 64\r
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\n" ); document.write( "\n" ); document.write( "\"%28y%2B3%29%5E2=100-64\" Subtract 64 from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"%28y%2B3%29%5E2=36\" Subtract\r
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\n" ); document.write( "\n" ); document.write( "\"y%2B3=%22%22%2B-sqrt%2836%29\" Take the square root of both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"y%2B3=sqrt%2836%29\" or \"y%2B3=-sqrt%2836%29\" Break up the \"plus/minus\"\r
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\n" ); document.write( "\n" ); document.write( "\"y%2B3=6\" or \"y%2B3=-6\" Take the square root of 36 to get 6.\r
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\n" ); document.write( "\n" ); document.write( "\"y=6-3\" or \"y=-6-3\" Subtract 3 from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"y=3\" or \"y=-9\" Subtract \r
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\n" ); document.write( "\n" ); document.write( "So the y-coordinates are \"y=3\" and \"y=-9\"\r
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\n" ); document.write( "\n" ); document.write( "So the two points are (-7,3) and (-7,-9)
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