document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=48717>Question 48717</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A bell rings every 2 hours, a second bell rings every 3 hours, and a third bell rings every 4 hours. If all 3 bells ring at 9:00 AM., at what time will all 3 bells next ring? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #32250 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=32250\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1/2+1/3+1/4 or the common denominator which all 3 numbers are factors of is 12 thus 12 hours after the beginning (9PM) they will all ring together. </SPAN>\n" );
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