document.write( "Question 48703: Solve by substitution.\r
\n" ); document.write( "\n" ); document.write( "3y = x + 5
\n" ); document.write( "3x - 9y = -10\r
\n" ); document.write( "\n" ); document.write( "3y = x + 5
\n" ); document.write( "3x - 9y = -10
\n" ); document.write( "=> -9y = -10 -3x
\n" ); document.write( "=> -9(x + 5) = -10 - 3x
\n" ); document.write( "=> -9x - 45 = -10 - 3x
\n" ); document.write( "=> -45 + 10 = -3x + 9x
\n" ); document.write( "=> -35 = 6x
\n" ); document.write( "=> -35/6 = x\r
\n" ); document.write( "\n" ); document.write( "3y = x + 5
\n" ); document.write( "=> 3y = -35/6 + 5
\n" ); document.write( "=> 3y = -35/6 +30/6
\n" ); document.write( "=> 3y = -5/6
\n" ); document.write( "=> y = -15/6
\n" ); document.write( "

Algebra.Com's Answer #32242 by dead_famous1991(7)\"\" \"About 
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\n" ); document.write( "3y = x + 5
\n" ); document.write( "3x - 9y = -10\r
\n" ); document.write( "\n" ); document.write( "3y = x + 5
\n" ); document.write( "3x - 9y = -10
\n" ); document.write( "=> -9y = -10 -3x
\n" ); document.write( "=> -9(x + 5) = -10 - 3x
\n" ); document.write( "=> -9x - 45 = -10 - 3x
\n" ); document.write( "=> -45 + 10 = -3x + 9x
\n" ); document.write( "=> -35 = 6x
\n" ); document.write( "=> -35/6 = x\r
\n" ); document.write( "\n" ); document.write( "3y = x + 5
\n" ); document.write( "=> 3y = -35/6 + 5
\n" ); document.write( "=> 3y = -35/6 +30/6
\n" ); document.write( "=> 3y = -5/6
\n" ); document.write( "=> y = -15/6
\n" ); document.write( "
\n" );