document.write( "Question 469955: I need help Identify the vertical and horizontal asymptotes of this function?\r
\n" ); document.write( "\n" ); document.write( "y=-3/(x-1)+2\r
\n" ); document.write( "\n" ); document.write( "please help me thank you soo very much i just get so confused i need it worked out so i can understand it
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Algebra.Com's Answer #322395 by MathLover1(20849)\"\" \"About 
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Write the function for which you are trying to find a vertical asymptote. usually rational functions, with the variable \"x\" somewhere in the denominator. When the denominator of a rational function approaches \"zero\", it \"has\" a \"vertical\"\"+asymptote\" (a line that passes through \"x=1\" and is parallel to y-axis).\r
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\n" ); document.write( "\n" ); document.write( "Find the value of x that makes the denominator equal to zero. \r
\n" ); document.write( "\n" ); document.write( "your function is \"y=-3%2F%28x-1%29%2B2\", you would solve the equation \"x-1+=+0\", which is \"x+=+1\". \r
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\n" ); document.write( "\n" ); document.write( "Take the limit of the function as \"x\" approaches the value you found from both directions. \r
\n" ); document.write( "\n" ); document.write( "For your example, as \"x\" approaches \"1\" from the left, \"y\" approaches positive \"infinity\" \r
\n" ); document.write( "\n" ); document.write( "and when \"1\" is approached from the right, \"y\" approaches negative \"infinity\" \r
\n" ); document.write( "\n" ); document.write( "This means the graph of the function splits at the discontinuity, jumping from negative infinity to positive infinity.\r
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\n" ); document.write( "\n" ); document.write( "\"+graph%28+500%2C+500%2C+-10%2C+10%2C+-10%2C+10%2C+-3%2F%28x-1%29%2B2%29+\"\r
\n" ); document.write( "\n" ); document.write( "another example for horizontal asymptotes:\r
\n" ); document.write( "\n" ); document.write( "Horizontal asymptotes can be found in a wide variety of functions. For this example, the function is \"y+=+x%2F%28x-1%29\".\r
\n" ); document.write( "\n" ); document.write( "Take the limit of the function as \"x\" approaches infinity. In this example, the \"\"1\"\" can be ignored because it becomes insignificant as \"x+\"approaches \"infinity\". Infinity minus \"1\" is \"still\"\"+infinity\". \r
\n" ); document.write( "\n" ); document.write( "So, the function becomes \"x%2Fx\", which equals \"1\". Therefore, the limit as \"x\" approaches infinity of \"x%2F%28x-1%29+=+1\"\r
\n" ); document.write( "\n" ); document.write( "Use the solution of the limit to write your asymptote equation. If the solution is a fixed value, there is a horizontal asymptote, but if the solution is infinity, there is no horizontal asymptote. If the solution is another function, there is an asymptote, but it is neither horizontal or vertical. For this example, the \"horizontal\" asymptote is \"y+=+1\"(a line that passes through \"y=1\" and is parallel to x-axis).\r
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