document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=469961>Question 469961</A>: <I><SPAN STYLE=\"word-break: break-all;\"> When the voltage across a certain resistance is V, the power delivered is P. If the voltage is doubled to 2V, the power delivered becomes\r<BR>\n" );
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document.write( "2P<BR>\n" );
document.write( "4p<BR>\n" );
document.write( "P<BR>\n" );
document.write( "P/2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #322386 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=322386\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> When the voltage across a certain resistance is V, the power delivered is P. If the voltage is doubled to 2V, the power delivered becomes <BR>\n" );
document.write( "V(x) = 2x<BR>\n" );
document.write( "----<BR>\n" );
document.write( "V(2x) = 2(2x) = 4x<BR>\n" );
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document.write( "Ans: 4P<BR>\n" );
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document.write( "cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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document.write( "2P<BR>\n" );
document.write( "4p<BR>\n" );
document.write( "P<BR>\n" );
document.write( "P/2<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );