document.write( "Question 469870: How do I check if this answer is really correct in elimination method.
\n" ); document.write( "1.) 3x - 2y = 6 SS={(4,3)}
\n" ); document.write( " 5x + 7y = 41\r
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\n" ); document.write( " 3x - 5y = 1
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Algebra.Com's Answer #322348 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "How do I check if this answer is really correct in elimination method.\r\n" );
document.write( "1.) 3x - 2y = 6              SS={(4,3)}\r\n" );
document.write( "    5x + 7y = 41\r\n" );
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document.write( "Substitute (4) for x  and (3) for y in both equations to see if \r\n" );
document.write( "you end up with a true equation:\r\n" );
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document.write( " 3(4) - 2(3) = 6      5(4) + 7(3) = 41\r\n" );
document.write( "      12 - 6 = 6          20 + 21 = 41\r\n" );
document.write( "           6 = 6               41 = 41\r\n" );
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document.write( "It is true both that 6 = 6 and that 41 = 41. Therefore (4,3) is a solution\r\n" );
document.write( "and {(4,3)} is the solution set.\r\n" );
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document.write( "2.) 5x - 2y = 8              SS={(2,1)}\r\n" );
document.write( "    3x - 5y = 1\r\n" );
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document.write( "Substitute (2) for x and (1) for y in both equations to see if \r\n" );
document.write( "you end up with a true equation:\r\n" );
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document.write( "5(2) - 2(1) = 8       3(2) - 5(1) = 1\r\n" );
document.write( "     10 - 2 = 8             6 - 5 = 1\r\n" );
document.write( "          8 = 8                 1 = 1\r\n" );
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document.write( "It is true both that 8 = 8 and that 1 = 1. Therefore (2,1) is a solution\r\n" );
document.write( "and {(2,1)} is the solution set.\r\n" );
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document.write( "[If either had turned out to be false like if instead of 8 = 8 it was 8 = 9\r\n" );
document.write( "1 = 2 or or something else that's false, then that would not be the solution.\r\n" );
document.write( "But in both problems here what were given as their solution set were correct.\r\n" );
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document.write( "Edwin
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