document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=469880>Question 469880</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One number is 6 times another. Their product is 12 times their sum. Find the numbers x and y. (Assume x  y.) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #322331 by </B><A HREF=/tutors/aboutme.mpl?userid=sofiyac><B>sofiyac(983)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sofiyac><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=sofiyac><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=322331\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> first number is x<BR>\n" );
document.write( "then second one is 6x<BR>\n" );
document.write( "x(6x)=12 sove for x<BR>\n" );
document.write( "6x^2=12<BR>\n" );
document.write( "x^2=2<BR>\n" );
document.write( "x=sqrt(2) so that's your first number, then the second one will be<BR>\n" );
document.write( "6sqrt(2) </SPAN>\n" );
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