document.write( "Question 48687: A solar collector is 2.5m long by 2.0m wide. It is held in place by a frame of uniform width around its outside edge. If the exposed collector area is 2.5m^2 , what is the width of the frame, to the nearest tenth of a centimeter? \n" ); document.write( "
Algebra.Com's Answer #32226 by stanbon(75887)\"\" \"About 
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A solar collector is 2.5m long by 2.0m wide. It is held in place by a frame of uniform width around its outside edge. If the exposed collector area is 2.5m^2 , what is the width of the frame, to the nearest tenth of a centimeter
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\n" ); document.write( "Draw the picture.
\n" ); document.write( "If the width of the frame is x the dimensions of the exposed panel are
\n" ); document.write( "length = 2.5-2x and width is 2-2x
\n" ); document.write( "EQUATION:
\n" ); document.write( " length * width = 2.5 m^2
\n" ); document.write( " (2.5-2x)(2-2x)=2.5
\n" ); document.write( " (2.5-2x)(1-x)= 1.25
\n" ); document.write( "2.5-2.5x-2x+2x^2=1.25
\n" ); document.write( "2x^2-4.5x+1.25=0
\n" ); document.write( "x=[4.5+-sqrt(4.5^2-4(2)(1.25)]/4
\n" ); document.write( "x=[4.5+-sqrt3.20156212..]/4
\n" ); document.write( "x=1.5723... or x=0.67767726...
\n" ); document.write( "Only x=0.67767726 is a viable answer as the other value
\n" ); document.write( "would give a 2x value greater than the width of length of the panel.
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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