document.write( "Question 469746: Assume a population with a mean of 136 and a standard deviation of 12. \r
\n" ); document.write( "\n" ); document.write( "A. Find the percentile rank of a score of 131.
\n" ); document.write( "a. 33.72%\r
\n" ); document.write( "\n" ); document.write( "b. 41.6%\r
\n" ); document.write( "\n" ); document.write( "c. 124%\r
\n" ); document.write( "\n" ); document.write( "d. 28.63%\r
\n" ); document.write( "\n" ); document.write( "B. Find the percentage of scores in between a score of 120 and a score of 140.
\n" ); document.write( "a. 20.00%\r
\n" ); document.write( "\n" ); document.write( "b. 40.82%\r
\n" ); document.write( "\n" ); document.write( "c. 53.75%\r
\n" ); document.write( "\n" ); document.write( "d. 13.33%\r
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Algebra.Com's Answer #322242 by edjones(8007)\"\" \"About 
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A.
\n" ); document.write( "z=(131-136)/12=-0.42
\n" ); document.write( "area under the normal curve below .42 is .3372 a.
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