document.write( "Question 469699: Word problems are so difficult for me to understand! Please help! Thanks.
\n" ); document.write( "For an engine with a displacement of 2.8L, the function given by the equation d=Cn^-2 can be used to determine the diameter size of the carburetor's opening, d, in millimeters, where n is the number of rpm's at which the engive achieves peak performace and C is a constant.
\n" ); document.write( "a. solve the equation for n.
\n" ); document.write( "b. Suppose the carburetor's opening is 84 mm and rpm's are 4480. Find the value of C that makes the equation true.
\n" ); document.write( "c. use the value of c that you found to determine the rpm's at which the engine produces peak power when the carburetor's opening is 81 mm.
\n" ); document.write( "

Algebra.Com's Answer #322223 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
\"+d+=+C%2An%5E%28-2%29+\"
\n" ); document.write( "(a)
\n" ); document.write( "Solve for \"n\"
\n" ); document.write( "Take the log of both sides
\n" ); document.write( "using the rule:
\n" ); document.write( "\"+log%28a%5Eb%29+=+b%2Alog%28a%29+\"
\n" ); document.write( "\"+log%28d%29+=+%28-2%29%2AC%2Alog%28n%29++\"
\n" ); document.write( "\"+log%28n%29+=+log%28d%29+%2F+%28-2%2AC%29+\"
\n" ); document.write( "Now use the above rule in reverse
\n" ); document.write( "\"+log%28n%29+=+log%28d%5E%281%2F%28-2C%29%29+\"
\n" ); document.write( "Use the rule:
\n" ); document.write( "If \"+log%28a%29+=+log%28b%29+\",
\n" ); document.write( "then \"+a+=+b+\"
\n" ); document.write( "\"+n+=+d%5E%281%2F%28-2C%29%29+\"
\n" ); document.write( "------------------
\n" ); document.write( "(b)
\n" ); document.write( "\"+d+=+84+\"
\n" ); document.write( "\"+n+=+4480+\"
\n" ); document.write( "Find \"C\"
\n" ); document.write( "\"+n+=+d%5E%281%2F%28-2C%29%29+\"
\n" ); document.write( "\"+4480+=+84%5E%281%2F%28-2C%29%29+\"
\n" ); document.write( "Let \"+1%2F%28-2C%29+=+x+\"
\n" ); document.write( "\"+84%5Ex+=+4480+\"
\n" ); document.write( "\"+x%2Alog%2884%29+=+log%284480%29+\"
\n" ); document.write( "\"+x+=+log%284480%29+%2F+log%2884%29+\"
\n" ); document.write( "\"+x+=+3.6513+%2F+1.92428+\"
\n" ); document.write( "\"+x+=+1.8975+\"
\n" ); document.write( "\"+1%2F%28-2C%29+=+1.8975+\"
\n" ); document.write( "\"+-2C+=+1%2F1.8975+\"
\n" ); document.write( "\"+C+=+-1%2F3.7950+\"
\n" ); document.write( "\"+C+=+-.2635+\"
\n" ); document.write( "
\n" );