document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=469686>Question 469686</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The following spinner is spun.  Given the conditions listed below, what is the probability that<BR>\n" );
document.write( "               a.  it lands on an odd number?<BR>\n" );
document.write( "               b.  it lands on a number divisible by 3?<BR>\n" );
document.write( "               c.  it does not land on 5,6, or 7?<BR>\n" );
document.write( "               d.  it lands on a number less than 4?\r<BR>\n" );
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document.write( "**Please note it's a regular spinner numberd 1-8** </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #322222 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=322222\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font face=\"Times New Roman\" size=\"+2\">\r<BR>\n" );
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document.write( "Probability is a fraction.  The denominator is the number of possible outcomes.  Hint:  Your spinner has 8 spots on it.  To eliminate having to deal with \"liners\" consider the line between segments on the right of a segment to belong to that segment.\r<BR>\n" );
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document.write( "The numerator of your fraction is the number of outcomes that you would consider a success.  So for part a), write out the numbers 1 through 8 and count the number of odd numbers.  That's your numerator for part a).  Remember to reduce your fraction once you have constructed it.\r<BR>\n" );
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document.write( "John<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE e^{i\pi} + 1 = 0\"><BR>\n" );
document.write( "My calculator said it, I believe it, that settles it<BR>\n" );
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