document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=469683>Question 469683</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need to know how to solve this equation. (x+18)(x-12)(x+3)>0. If anyone can help, I would appreciate it, thanks in advance. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #322219 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=322219\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First, find the zeros of <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=%28x%2B18%29%28x-12%29%28x%2B3%29 ALIGN=MIDDLE  ALT=\"y=%28x%2B18%29%28x-12%29%28x%2B3%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >. \r<BR>\n" );
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document.write( "(x+18)(x-12)(x+3)=0\r<BR>\n" );
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document.write( "x+18=0 or x-12=0 or x+3=0\r<BR>\n" );
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document.write( "x=-18, x=12, or x=-3\r<BR>\n" );
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document.write( "In ascending order, the zeros are: -18,-3,12\r<BR>\n" );
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document.write( "Now in the interval <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \left(-\infty,-18\right)\">, (x+18)(x-12)(x+3) is negative. Simply plug in any negative number less than -18 to see this (eg: plug in x=-20 to get (-20+18)(-20-12)(-20+3)=-1088)\r<BR>\n" );
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document.write( "In the interval <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \left(-18,-3\right)\">, (x+18)(x-12)(x+3) is positive. Simply plug in any number in the interval to see this (eg: plug in x=-5 to get (-5+18)(-5-12)(-5+3)=442) \r<BR>\n" );
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document.write( "In the interval <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \left(-3,12\right)\">, (x+18)(x-12)(x+3) is negative. Simply plug in any number in the interval to see this (eg: plug in x=0 to get (0+18)(0-12)(0+3)=-648) \r<BR>\n" );
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document.write( "Finally, in the interval <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \left(12,\infty\right)\">, (x+18)(x-12)(x+3) is positive. Simply plug in any number greater than 12 to see this (eg: plug in x=50 to get (50+18)(50-12)(50+3)=136952) \r<BR>\n" );
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document.write( "So the following intervals make (x+18)(x-12)(x+3) positive: <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \left(-18,-3\right)\"> and <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \left(12,\infty\right)\">\r<BR>\n" );
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document.write( "So combine them with a union symbol to get the final answer: <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \left(-18,-3\right)\cup\left(12,\infty\right)\">\r<BR>\n" );
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document.write( "Here's a graph to visually confirm this\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+graph%28+500%2C+500%2C+-20%2C+20%2C+-1500%2C+1500%2C+%28x%2B18%29%28x-12%29%28x%2B3%29%29+ ALIGN=MIDDLE  ALT=\"+graph%28+500%2C+500%2C+-20%2C+20%2C+-1500%2C+1500%2C+%28x%2B18%29%28x-12%29%28x%2B3%29%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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