document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=469643>Question 469643</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do you solve    \"find three consecutive integers such that twice the smallest is 12 less more than the largest.\"  i know to do \r<BR>\n" );
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document.write( "Let n=1st CI<BR>\n" );
document.write( "n+1=2nd CI<BR>\n" );
document.write( "n+2= 3rd CI<BR>\n" );
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document.write( "But how do you get the varbal expression.  how do you find twice the smallest and the largest.  what is that. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #322198 by </B><A HREF=/tutors/aboutme.mpl?userid=ccs2011><B>ccs2011(207)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ccs2011><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ccs2011><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=322198\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Twice the smallest just means 2 times the lowest integer(n)<BR>\n" );
document.write( "12 less means you subtract 12 from the highest integer(n+2)<BR>\n" );
document.write( "**Note i think you left something out of the question, Im going to assume its \"12 less than 3 times the largest\" since that provides the first case in which there is a valid solution**<BR>\n" );
document.write( "Equation:<BR>\n" );
document.write( "2n = 3(n+2) - 12<BR>\n" );
document.write( "2n = 3n - 6<BR>\n" );
document.write( "Subtract 3n on both sides<BR>\n" );
document.write( "-n = -6<BR>\n" );
document.write( "Flip signs<BR>\n" );
document.write( "n = 6<BR>\n" );
document.write( "Therefore the 3 consecutive integers are 6,7,8 </SPAN>\n" );
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