document.write( "Question 469643: how do you solve \"find three consecutive integers such that twice the smallest is 12 less more than the largest.\" i know to do \r
\n" ); document.write( "\n" ); document.write( "Let n=1st CI
\n" ); document.write( "n+1=2nd CI
\n" ); document.write( "n+2= 3rd CI
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\n" ); document.write( "But how do you get the varbal expression. how do you find twice the smallest and the largest. what is that. \n" ); document.write( "

Algebra.Com's Answer #322197 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!

 
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document.write( "Hi,
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document.write( "Yes! Let n, (n+1) and (n+2) represent the three consecutive integers
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document.write( "Question states***
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document.write( " 2n = (n+2)-12
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document.write( "Solving for x
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document.write( "  n = -10  the three consecutive integers are -10,-9,-8\r
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document.write( "CHECKING our Answer***
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document.write( " -20 = -8 - 12 = -20 \n" );
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