document.write( "Question 469620: please help me! can someone pls? :(\r
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\n" ); document.write( "\n" ); document.write( "if y varies inversely as x, and y=27 when x=4, find y when x=12\r
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Algebra.Com's Answer #322185 by Tatiana_Stebko(1539)\"\" \"About 
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1 way:
\n" ); document.write( " y varies inversely as x, so if x increase by 3 (\"12%2F4=3\"), then y decrease by 3
\n" ); document.write( "\"y=27%2F3=9\"
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\n" ); document.write( "\n" ); document.write( "2 way:
\n" ); document.write( "if y varies inversely as x, then \"y=k%2Fx\", y=27 when x=4, so \"27=k%2F4\"=>\"k=27%2A4=108\"=> \"y=108%2Fx\"
\n" ); document.write( "when x=12, then \"y=108%2F12=9\"
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