document.write( "Question 469553: (y^3-3y^2)/(y^2+2y-15)=(13y-40)/(y+5) \n" ); document.write( "
Algebra.Com's Answer #322173 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
 
\n" ); document.write( "Hi,
\n" ); document.write( "\"%28y%5E3-3y%5E2%29%2F%28y%5E2%2B2y-15%29=%2813y-40%29%2F%28y%2B5%29\"
\n" ); document.write( "\"y%5E2cross%28%28y-3%29%29%2F%28%28y%2B5%29cross%28%28y-3%29%29%29=%2813y-40%29%2F%28y%2B5%29\"
\n" ); document.write( " y^2 = 13y - 40
\n" ); document.write( " y^2 - 3y + 40 = 0
\n" ); document.write( " factoring
\n" ); document.write( " (y-8)(y-5) = 0
\n" ); document.write( " (y-8)= 0 y = 8
\n" ); document.write( " (y-5)= 0 y = 5\r
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