document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=469602>Question 469602</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Selma needs to prepare 180 pounds of coffee selling for $4.72 per pound. She plans to do this by blending together a high-quality bean costing $5.50 per pound and a cheaper pound at $3.50 per pound. To the nearest pound find out how much high quality beans and how many of the cheaper beans coffee beans should be blended. She should blend _____ lbs of the higher costing bean.<BR>\n" );
document.write( "She should blend ______ lbs of the cheaper costing bean. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #322170 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=322170\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Selma needs to prepare 180 pounds of coffee selling for $4.72 per pound. She plans to do this by blending together a high-quality bean costing $5.50 per pound and a cheaper bean at $3.50 per pound. To the nearest pound find out how much high quality beans and how many of the cheaper beans coffee beans should be blended.<BR>\n" );
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document.write( "Equations:<BR>\n" );
document.write( "Quantity Eq:: t + f = 180 lbs<BR>\n" );
document.write( "Value Eq::: 3.50t+5.50f=4.72*180<BR>\n" );
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document.write( "Multiply thru the Quantity Eq by 350.<BR>\n" );
document.write( "Multiply thru the Value Eq by 100.<BR>\n" );
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document.write( "350t + 350f = 350*180<BR>\n" );
document.write( "350t + 550f = 472*180<BR>\n" );
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document.write( "Subtract and solve for \"f\":<BR>\n" );
document.write( "200f = 122*180<BR>\n" );
document.write( "f = (9/10)122<BR>\n" );
document.write( "f = 109.8 lbs (amt. of higher priced coffee needed)<BR>\n" );
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document.write( "Solve for \"t\":<BR>\n" );
document.write( "t + f = 180<BR>\n" );
document.write( "t = 180-109.8 = 70.2 lbs (amt. of lower priced coffee needed)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "=======================================\r<BR>\n" );
document.write( "\n" );
document.write( " She should blend _____ lbs of the higher costing bean.<BR>\n" );
document.write( "She should blend ______ lbs of the cheaper costing bean.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );