document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=469583>Question 469583</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An artist has 30kg of an alloy that is 45% copper. How many kilograms of a second alloy that is 70% copper should be mixed with the first alloy to get a new alloy that is 60% copper </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #322158 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=322158\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 30x.45=13.5<BR>\n" );
document.write( "13.5+.7(n)=.6(30+n)<BR>\n" );
document.write( "13.5+.7n=18+.6n<BR>\n" );
document.write( ".1n=4.5<BR>\n" );
document.write( "n=4.5/.1=45 kilograms of 70% copper needed for the alloy.. </SPAN>\n" );
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