document.write( "Question 48672: I need help in finding the value of X:\r
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Algebra.Com's Answer #32214 by longjonsilver(2297)\"\" \"About 
You can put this solution on YOUR website!
log2 8 = x\r
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\n" ); document.write( "\n" ); document.write( "this is equivalent to asking \"what power of 2 is needed to equal 8\"? Answer is 3, since \"2%5E3\" is 2*2*2 which is 8.\r
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\n" ); document.write( "\n" ); document.write( "You need to become familiar with this form of question rather than having it written as \"2%5Ex+=+8\". They are 2 opposite forms of the same problem just like 3-x=7 is just the same as asking x=3-7.\r
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