document.write( "Question 469446: 1) how many gallons each of 25% alcohol and 35% alcohol should be mixed to get 20 gallons of 32% alcohol? \n" ); document.write( "

Algebra.Com's Answer #322135 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!

 
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document.write( "Hi,
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document.write( "mixed to get 20 gallons
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document.write( "Let x and (20-x) represent the amount of the  35% and 25% solutions respectively
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document.write( "Question states*** 
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document.write( " mixing to get 20 gal of 32% alcohol
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document.write( "   .35x + .25(20-x) = .32*20G
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document.write( "Solving for x
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document.write( "     .10x  = .07*20G =  
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document.write( "      x = 14G, the amount of the 35% Solution.  6G of the 25% solution\r
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document.write( "CHECKING our Answer***
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document.write( ".35*14 + .25*6  = 4.9 + 1.5 = .32*20 = .64 \n" );
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