document.write( "Question 469447: 2) How many Liters each of 15% acid and 33% acid should be mixed to get 120 Liters of 21% acid? \n" ); document.write( "

Algebra.Com's Answer #322134 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi,
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document.write( "mixed to get 120 Liters 
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document.write( "Let x and (120-x) represent the amount of the  33% and 15% solutions respectively
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document.write( "Question states*** 
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document.write( " mixing to get 120 Liters of 21% acid?
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document.write( "   .33x + .15(120-x) = .21*120L
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document.write( "Solving for x
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document.write( "     .18x  = .06*120L =  7.2L
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document.write( "      x = 40L, the amount of the 33% Solution.  80L of the 15% solution\r
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document.write( "CHECKING our Answer***
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document.write( "  .33*40 + .15*80 = 13.2 + 12 = 25.2 = .21*120 \n" );
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