document.write( "Question 469442: log2 7x + log2 x = 3 \n" ); document.write( "
Algebra.Com's Answer #322091 by ccs2011(207)\"\" \"About 
You can put this solution on YOUR website!
use log property
\n" ); document.write( "\"log+x+%2B+log+y+=+log+xy\"
\n" ); document.write( "So
\n" ); document.write( "\"log+7x+%2B+log+x+=+log+7x%5E2\"
\n" ); document.write( "Equation becomes
\n" ); document.write( "\"log+7x%5E2+=+3\"
\n" ); document.write( "Rewrite in exponential form
\n" ); document.write( "base of log becomes base of right side with 3 as exponent
\n" ); document.write( "\"7x%5E2+=+2%5E3\"
\n" ); document.write( "\"7x%5E2+=+8\"
\n" ); document.write( "Divide by 7 on both sides
\n" ); document.write( "\"x%5E2+=+8%2F7\"
\n" ); document.write( "Take square root of both sides
\n" ); document.write( "
\n" ); document.write( "
\n" );