document.write( "Question 469433: how much 20% acid must be added to 3000 ml of a 50% soltion to create a 25% solution. How much solution will be created? \n" ); document.write( "

Algebra.Com's Answer #322073 by ccs2011(207) $\"\"$ $\"About$

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Write a balanced equation:
\n" ); document.write( " $\"0.2x+%2B+0.5%283000%29+=+.25%28x%2B3000%29\"$
\n" ); document.write( "Solve for x
\n" ); document.write( "Distribute right side
\n" ); document.write( " $\"0.2x+%2B+1500+=+.25x+%2B+750\"$
\n" ); document.write( "Subtract .25x on both sides
\n" ); document.write( " $\"-.05x+%2B+1500+=+750\"$
\n" ); document.write( "Subtract 1500 on both sides
\n" ); document.write( " $\"-.05x+=+-750\"$
\n" ); document.write( "Divide by -.05 on both sides
\n" ); document.write( " $\"x+=+15%2C000\"$
\n" ); document.write( "Therefore, 15,000 ml of 20% solution must be added \n" ); document.write( "

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