document.write( "Question 469392: how much pure acid must be added to 500 ml of an 8% acid solution to make a 20% acid solution? \n" ); document.write( "

Algebra.Com's Answer #322035 by jorel1380(3719) $\"\"$ $\"About$

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n+500(.08)=.2(n+500)
\n" ); document.write( "n+40=.2n+100
\n" ); document.write( ".8n=60
\n" ); document.write( "n=60/.8=75 ml of pure acid necessary for the solution.. \n" ); document.write( "

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