document.write( "Question 48653: Here are a few problems that were given as a summer test in preparation for AP Calculus. I would appreciate it if I could recive soem help. The test is due tommorrow. Thank you in advance for your help.\r
\n" ); document.write( "\n" ); document.write( "2. The three sides of a triangle are 9 inches, 11 inches, and 12 inches. Joining the midpoints of the sides of the original triangle forms a new triangle. Find the perimeter of the new triangle.\r
\n" ); document.write( "\n" ); document.write( "7. The hypotenuse of a right triangle is 15 inches, and the altitude upon the hypotenuse is 6 inches. Find the segme, ts of the hypotenuse.\r
\n" ); document.write( "\n" ); document.write( "8. A chord AB is 12 inches; E is its midpoint. Another chord, CD, 13 inches in length, cuts AB at E. Find CE and ED.\r
\n" ); document.write( "\n" ); document.write( "14. Find the circumference of a circle if an inscribed angle of 18 degrees intercepts an arc 6 inches long.\r
\n" ); document.write( "\n" ); document.write( "Thanks agian
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Algebra.Com's Answer #32202 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
2. The three sides of a triangle are 9 inches, 11 inches, and 12 inches. Joining the midpoints of the sides of the original triangle forms a new triangle. Find the perimeter of the new triangle.
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\n" ); document.write( "Draw the picture.
\n" ); document.write( "Notice the three parallelograms you formby connecting the mid-points.
\n" ); document.write( "Each of the sides of the inner triangle is half of one of the outside sides.
\n" ); document.write( "Perimeter = 6+4.5+5.5=16
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\n" ); document.write( "7. The hypotenuse of a right triangle is 15 inches, and the altitude upon the hypotenuse is 6 inches. Find the segme, ts of the hypotenuse.
\n" ); document.write( "Draw the picture.
\n" ); document.write( "The antitude forms two similar triangles.
\n" ); document.write( "The hypotenuse of the original triangle has two pieces: x and 15-x.
\n" ); document.write( "PROPORTION:
\n" ); document.write( "x/6=6/(15-x)
\n" ); document.write( "15x-x^2=36
\n" ); document.write( "x^2-15x+36=0
\n" ); document.write( "(x-3)(x-12)=0
\n" ); document.write( "x=3 inches ; 15-x=12 inches
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\n" ); document.write( "8. A chord AB is 12 inches; E is its midpoint. Another chord, CD, 13 inches in length, cuts AB at E. Find CE and ED.
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\n" ); document.write( "Draw the picture.
\n" ); document.write( "You have formed two similar triangles because angle C and angle B
\n" ); document.write( "intercept the same arc, so are equal. Also angle A and angle D intercept
\n" ); document.write( "the same are, so are equal. And the vertical angles at E are equal.
\n" ); document.write( "So the triangles are similar.
\n" ); document.write( "Let CE=x, then ED = 13-x.
\n" ); document.write( "AE = 6 = EB
\n" ); document.write( "Proportion:
\n" ); document.write( "x/6 = 6/13-x
\n" ); document.write( "13x-x^2=36
\n" ); document.write( "x^2-13x+36=0
\n" ); document.write( "(x-9)(x-4)=0
\n" ); document.write( "x=9 then 13-x=4 or vice versa
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\n" ); document.write( "14. Find the circumference of a circle if an inscribed angle of 18 degrees intercepts an arc 6 inches long.
\n" ); document.write( "PROPORTION:
\n" ); document.write( "circumference/6 = 360 degrees/ 18 degrees
\n" ); document.write( "circum = 6(360/18)= 120 inches
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\n" ); document.write( "Cheers
\n" ); document.write( "Stan H.\r
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