document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=469359>Question 469359</A>: <I><SPAN STYLE=\"word-break: break-all;\"> (1)Ten more than 6 times Harold's age is the same as 4 times his age increased by 40. Find Harold's age.\r<BR>\n" );
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document.write( "(2)  Using d=rt, find d for r=65mi/h and t=9hours\r<BR>\n" );
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document.write( "(3) If steve's age is decreased by 12 years, and that difference is multiplied by 3, the result is 24 years. Find steve's age  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #322005 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=322005\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 6H+10=4H+40<BR>\n" );
document.write( "2H=30<BR>\n" );
document.write( "H=15<BR>\n" );
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document.write( "65 mph x 9 hours=585  miles<BR>\n" );
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document.write( "3(s-12)=24<BR>\n" );
document.write( "3s-36=24<BR>\n" );
document.write( "3s=60<BR>\n" );
document.write( "s=20<BR>\n" );
document.write( "Steve is 20.. </SPAN>\n" );
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