document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=469355>Question 469355</A>: <I><SPAN STYLE=\"word-break: break-all;\"> one positive numer is 4 more than 3 times another positive number and their product is 39 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #322004 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=322004\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let n be first number<BR>\n" );
document.write( "Second number equals 3n+4<BR>\n" );
document.write( "n(3n+4)=39<BR>\n" );
document.write( "3n2+4n-39=0<BR>\n" );
document.write( "(3n+13)(n-3)=0<BR>\n" );
document.write( "n=-13/3 or 3<BR>\n" );
document.write( "Throwing out the negative answer, we get the two numbers to be 3 and 13.. </SPAN>\n" );
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