document.write( "Question 48654: A chemist has a 90% solution of sulfuric acid and a 70% solution of the same acid. How many gallons of each must be mixed in order to make 200 gallons of a 75% solution\r
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Algebra.Com's Answer #32199 by stanbon(75887)\"\" \"About 
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A chemist has a 90% solution of sulfuric acid and a 70% solution of the same acid. How many gallons of each must be mixed in order to make 200 gallons of a 75% solution
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\n" ); document.write( "90% solution DATA:
\n" ); document.write( "amount= x gals. ; amount of active ingredient= 0.90x gals
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\n" ); document.write( "70% solution DATA:
\n" ); document.write( "amount= 200-x gals ; amount of active ingredient= 0.70(200-x)=140-0.7 gals
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\n" ); document.write( "Mixture DATA:
\n" ); document.write( "amount = 200 gals ; amount of acive ingredient=0.75(200)= 150 gals
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\n" ); document.write( "EQUATION:
\n" ); document.write( "active + active = active
\n" ); document.write( "0.9x + 140-0.7x=150
\n" ); document.write( "0.2x=10
\n" ); document.write( "x=50 gals (Amount of 90% solution)
\n" ); document.write( "200-x=150 gals. (amount of 70% solution)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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