document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=469226>Question 469226</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me to solve:  Suppose that 2 cards are dealt from a standard 52-card poker deck.  Let A be the event that the sum of the 2 cards is 8(assume that aces equal 1)  How many outcomes are in A?<BR>\n" );
document.write( "This is how I started:  Combinations that equal 8: A+7, 2+6, 3+5, 4+4, 5+3, 6+2, 7+A.  Considering there are 4 cards for each number and add them together is 8 cards per set of combinations.  There are 7 combinations, so 7*8=56.  How does that sound? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #321941 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=321941\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> There are 4 aces and 4 sevens=4*4=16<BR>\n" );
document.write( "Remember that we are looking for combinations not permutations. The order in which<BR>\n" );
document.write( "the cards are dealt is not important.<BR>\n" );
document.write( "There are 16 possible combinations of A,7.<BR>\n" );
document.write( "Another 16 for 6,2 and 16 for 3,5<BR>\n" );
document.write( "16*3=48<BR>\n" );
document.write( "4C2=6 a special case for 4,4<BR>\n" );
document.write( ".<BR>\n" );
document.write( "48+6=54<BR>\n" );
document.write( "You were close.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );