document.write( "Question 469066: i need complete solution for this logical proof
\n" ); document.write( "AB+CD=(A+C)(A+D)(B+C)(B+D)\r
\n" ); document.write( "\n" ); document.write( "Where:
\n" ); document.write( " A+BC=(A+B)(A+C)
\n" ); document.write( " A+AB=A
\n" ); document.write( " A+B=B+A
\n" ); document.write( " A= AA
\n" ); document.write( " A+A=A
\n" ); document.write( "

Algebra.Com's Answer #321869 by robertb(5830)\"\" \"About 
You can put this solution on YOUR website!
(A+C)(A+D)(B+C)(B+D)
\n" ); document.write( "=((A+C)(A+D))((B+C)(B+D)) ASSUMING associativity\r
\n" ); document.write( "\n" ); document.write( "= (A + CD)(B + CD) from A+BC=(A+B)(A+C)\r
\n" ); document.write( "\n" ); document.write( "= (CD + A)(CD + B) from A+B=B+A\r
\n" ); document.write( "\n" ); document.write( "= CD + AB from A+BC=(A+B)(A+C)
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